Question

estion 13 From the table of thermodynamic data shown here calculate the following thermodynamic properties at 298 K for 2 Alis) + 3 Cl2(g) 2 AICI3(s) 솨f.-1408,4 kJ/mol Consult Textbook Your Answers a) ASsys JK1 mol-1 JKt mott Complete parts al and b first Submit>

Answer 1

Given ΔH^o =ΔH_sys = -1408 kJ/mol

The given reaction is 2Al(s) + 3Cl2(g) ---> 2AlCl3(s) :

ΔS_sys = ΔS⁰_products – ΔS⁰_reactants

ΔS_sys = [(2x ΔS⁰_AlCl3(s) )]- [( 2 x ΔS⁰_Al(s) )+ (3 x ΔS⁰_{Cl2 (g)} )]

          = [2x109.29)] - [(2x28.33) + (3x222.97)]

        = -507.0 J/(mol-K)

          = -0.507 kJ/(mol-K)

T= temperature = 298 K

We know that ΔS_surr = −(ΔH_sys /T)

                                = -[-1408 (kJ/mol )x (1000 J/kJ)]/298 K

                                = 4.725 x10³ J/(mol-K)

                                = 4.725 kJ/(mol-K)

Also ΔS_univ = ΔS_sys+ΔS_surr

   = -0.507 + 4.725 kJ/(mol-K)                  

                   = 4.218 kJ/(mol-K)

                   = 4218 J/(mol-K)

Therefore ΔS_univ = 4218 J/(mol-K)