I have the answer to this but I do not know how i got there. An
explanation would be much appreciated (:Given the following reactions N2 (g) + O2 (g) → 2NO (g) ΔH = +180.7 kJ 2N2O (g) → O2 (g) + 2N2 (g) ΔH = -163.2 kJ the enthalpy of reaction for 2N2O (g) → 2NO (g) + N2 (g) is ________ kJ.
Recitation Exercise 9 CHEM 1411 Name Partners Instructor Day of Week 1. Given the equations: N2(g) + O2(g) → 2NO(g) AH = +180.7 kJ 2NO(g) + O2(g) → 2NO2(g) AH =-113.1 kJ 2N20(g) → 2N2(g) + O2(g) AH = -163.2 kJ Calculate the change in enthalpy for the reaction: N2O(g) + NO2(g) → NO(g) 2. An electron in a carbon atom makes a transition from n=2 to n=3. a) Does this transition require energy or emit energy? b) Can you...
Use the standard reaction enthalpies given below to determine AHⓇ rxn for the following reaction: 2 NO(g) + O2(g) + 2NO2(g) AHørxn = ? Given: N2(E) + O2(g) + 2NO(g) AH®rxn = +183 kJ AHørxn = +33 kJ 1/2N2(E) + O2(g) + NO2(g) -150. kJ O-117 kJ O-333 kJ +115 kJ +238 kJ
13. Given the data N,(g) + 0.9-2N0(g) 2N0(g) + O2(g) → 2NO2(g) 2N20(g)-> 2 N2(g) + O2(g) M,-+190.4 kJ/mol AH-=-129.3 kJ/mol A, =-58.7 kJ/mol For the "mol" of the units above, it means that the reaction coefficients are counted iin numbers of moles. Use Hess's law to calculate AH in kJ/mol for the reaction N20(g) + N2 (g) + 20, → 3N0(g) + NO2(g) 14. Compare the following two unbalanced violent chemical reactions that could be used in rocket engines:...
Given the standard enthalpy changes for the following two reactions: (1) N2(g)-202(g) N204(g) ΔΗ 9.2 kJ (2) 2N2O(2N2()-O2() what is the standard enthalpy change for the reaction: (3) 2N20(D -302( 2N204() AH-? kJ
21. Calculate the energy of a photon whose wavelength is 447 nm 8 pts each 22. Given the following equation, calculate how much so, gas (in grams) is formed when 25 kJ of heat are released 2 ZnS (s) + 3 02 (6) ► 2 ZnO (s) + 2 SO. (6) AH = -878.2 kJ 23. Given the following reactions, N2 (e) + O2(g) → 2 NO (€) 2 NO (g) + O2(g) → 2 NO2(g) 2 N2O(g) → 2...
Calculate the enthalpy of the reaction: 2 NO(g) + O2(g) --> 2 NO2(g) given the following reactions and enthalpies of formation: 1/2 N2(g) + O2(g) → NO2(g), ΔH = 33.2 kJ 1/2 N2(g) + 1/2 O2(g) → NO(g), ΔH = 90.2 kJ
**********Please explain the following question in detail********** Calculate the standard enthalpy change, ΔH°rxn, in kJ for the following chemical equation, using only the thermochemical equations below: 2NO(g) + 2NO3(g) → 4NO2(g) Report your answer to three significant figures in scientific notation. Equations: ΔH°rxn (kJ) NO(g) + 1/2O2(g) → NO2(g) -56.5 1/2N2(g) + O2(g) → NO2(g) 33.8 N2(g) + 3O2(g) → 2NO3(g) 142.3
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: 2NO(g) + O2(g) → 2NO2(g) ΔH°rxn = ? (6 Pts.) Given: N2(g) + O2(g) → 2NO(g) ΔH°rxn = +183 kJ N2(g) + 2O2(g) → 2NO2(g) ΔH°rxn = +66 kJ
Calculate the enthalpy of the reaction 2NO(g)+O2(g)→2NO2(g) Given the following reactions and enthalpies of formation: N2(g) + 2O2(g)→ 2NO2(g), ΔH∘ = 66.4kJ N2(g)+ O2(g)→ 2 NO(g), ΔH∘=180.4 kJ Please explain the steps as well!