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A uniform line of charge of length V/2 lying between x = 0 and x = 1/2 is charged with 2Q os shown in the figure. Which of th

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Answer #1

E = k \int_{0}^{L/2} \frac{\lambda}{(3L-x)^{2}}dx

Since \: \lambda = 2Q/L

Therefore ,

E = k \int_{0}^{L/2} \frac{2Q/L}{(3L-x)^{2}}dx

or

E =\frac{2kQ}{L} \int_{0}^{L/2} \frac{dx }{(3L-x)^{2}}

Thus second option is correct.

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