Question

Compound A reacts with sodium propynide B to give product C. The observed rate of the reaction is 4 x 10-5 M.s 1 when concentrations of A and B were 0.1 M and 0.2 M respectively. Determine the rate of the reaction when the concentration of Ais 0.3 M and that of B is 0.4 M. PS: Please follow this format for your answer exp: 1.2 x 10-3 (one decimal, no units and no superscript) EtOH с Na + Br A B

Answer 1

Rate expression:

Rate = K [A]^x[B]^y

where x and y are order

K is rate constant.

As, the reaction is one step reaction, so order of A and B will be same as stoichiometric coefficient i.e 1

4 x 10^-5 M s^-1 = K [0.1 M][0.2 M]

K = 2 x 10^-3 M^-1​​​​​ s^-1

When, [A] = 0.3 M

[B] = 0.4 M

So, Rate = (2 x 10^-3 M^-1 s^-1)( 0.3 M) (0.4 M)

= 2.4 x 10^-4 M^-1s^-1