A force F = 1.8 i + 2.5 j N is applied at the point x = 3.0 m, y = 0 m. (a) Find the torque about the origin. k N
A force acting on a particle in the xy plane at coordinates (x, y) is given by vector F = (F_0/r) (y hat i - x hat j), where F_0 is a positive constant and r is the distance of the particle from the origin. Show that the magnitude of this force is F_0. Show that the direction of vector F is perpendicular to vector r = x hat i + y hat j.
A force is applied at a distance away from an objects axis of rotation. Given F->=5i-2j and r->=I+3j, calculate the torque acting on the object from this force.
A metal bar is in the xy-plane with one end of the bar at the origin. A force F =(6.12 N )i+(-3.27 N )j is applied to the bar at the point x = 2.07 m, y = 3.02 m. Part A What is the position vector for the point where the force is applied?Part B What is the magnitude of the torque with respect to the origin produced by F?
1) Force F =(-8.00 N){+(6.00 N) j acts on a particle with position vector r = (3.00 m)i +(4.00 m)j. What are (a) the torque on the particle about the origin, in unit-vector notation, and (b) the angle between the directions of r and F?
Given a force F = ( 2.03 i - 3.89 j ) N acting through a displacement d = ( - 2.90 i + 5.30 j ) m, find the work done by this force.
What is the magnitude of the torque in Nm? Whole numbers only here. i j k mean the unit vectors in the x y and z direction respectively. Normally written with a cute little hat or ^ on top of them. Remember that torque = r X F. position vector = r = 3.29 i + 4.06 j + 5.47 k where r is in metres and applied force = F = 581 i + 721 j - 838 k...
1. (a) Force F = -21 - 4 (N) is applied to a metal bar in the x-y plane with one end of the bar at the origin. The point on the bar of application of the force is (x - 2m, y m). Use the position vector (1) of the point of action of the force to find the magnitude and direction of the torque. Hint: Employ method of determinant to find cross product (6pts) Show working (2pts) Magnitude...
Force F = (2.0 N) i + (-7.0 N) k acts on a pebble with position vector r = (0.60 m) j + (-0.9 m) k, relative to the origin. PLEASE SHOW WORK! (a) What is the resulting torque acting on the pebble about the origin? [ ] N·m i + [ ] N·m j + [ ] N·m k (b) What is the resulting torque acting on the pebble about a point with coordinates (2.0 m, -8.0 m, 6.0...
A force in the xy plane is given by = where F is a constant and r=. a.) Find the magnitude of the force. b.)Show that is perpendicular to =x c.) Find the work done by this force on a particle that moves once around a circle of radius 5 m centered at the origin. A force in the xy plane is given by hat{i}+yhat{j} c.) Find the work done by this force on a particle that moves once around...