Homework Answers
Flow rate
Q=(1*10-3)/5 =2*10-4 m/s
speed of water emerge from shower head
V=Q/NA =(2*10-4)/42*(pi*0.0022)
V=0.3789 m/s
b)
From Bernoulli's equation
P1+(1/2)pV12+pgh1=P2+(1/2)pV22+pgh2
(P2-P1)+pg(h2-h1)+(1/2)pV22 =(1/2)pV12
(105-1.5*105)+1000*10*5.1+(1/2)*1000*0.37892=(1/2)*1000*V12
V1=1.464 m/s
c)
From continuity equation
A1V1=A2V2
A1*1.466=0.3789*(42*pi*0.0022)
A1=1.364*10-4 m2
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