Question

A truck moving at 35.0 mph collides head on with a car traveling in the opposite direction. The mass of the car is 550 kg, the mass of the truck is 2200 kg. During the collision both vehicles come to a stop in 0.150 s as the front end of both vehicles’ crumples. What was the acceleration of the car? Assume that during the collision the acceleration of each vehicle is constant. Also, assume that frictional force are small compared to the forces compared to the contact forces between the vehicles during the colision

Answer 1

U2=2 mass of call M2)=55019. U,= 35 mph модX + Гулче (M, J = 20 M-२२०० time (t) = 0.150 S Truck speed of Truck(U)= 35 mph 101=35X0.447= 15.645m/s) (imph=0.447m/s) Initial momentum of the system Peo= m. Uit MzU2 = 2200x151645+ (-550U2) Pe = (34419-55042) 0 [-vesign fer opposite Final momentum of the system, t direction of con Pg = 0 As both stops, U=0, V2 =] from conservation of momentum, Peopf => 34419-550U2=0=> U2 = 34419 550 U2= 62.50m/s/U2 speed of car before Collision (Initted spull Now can stops after t= 0.150 Sre ets final velocity ofth,t=0.150S, 82²0 From equation Vza Uzt at 50 = 62.50+ ax 0.015 a= - 62.50 - 4172 m/32 - 0.015 I a= 4172 M/S2 / Eve sign shows/ And I retardation :