Question

This should be done using RStudio

2 [10 marks] Using vector syntax, and subsetting, solve the following three sub-questions. Note that while you can solve these manually, that is not the intention of the problem, and doing so will result in zero points. Begin by creating two vectors: one of all of the multiples of 5 between 1 and 100 (x) and one of all of the multiples of 3 between 1 and 100 (). (a) How many multiples of 5 are also multiples of 3, between 1 and 100? b) How many multiples of 5 are equal to 3k +1, that is, 1 higher than a multiple of 3? (c) How many multiples of 3 are equal to 5k+2, that is, 2 higher than a multiple of 5?

Answer 1

Multiple 5 Multiple of 3 a) Multiples of both 5 & 3 ae 15, 30, 45, 60, 75, 90 c) 5kt2 So, total 6 3kt1 From all these values the multiples of 3 are 12, 27,42, 57, 72, 87 15 64 from all these values 67 the multiples of 5 are 70 10, 25, 40, 55, 70, 85, 100 73 Total- 76 79 17 22 Total 5 21 16 37 87 47 93 57 Зб 31 37 97 72 75 100 51 87 57 52 97