[S] v
(nM) (nM s-1)
1.25 1.10
3.60 4.15
5.83 6.54
7.34 9.38
9.12 11.71
Calculate the Vmax and Km values using the following methods with work.
Line weaver Burke:
Hanes Woolf:
Eadie Hofstee:
Lineweaver Burk:
Equation:

| S | V | 1/S | 1/V |
| 1.25 | 1.1 | 0.8 | 0.909091 |
| 3.6 | 4.15 | 0.277778 | 0.240964 |
| 5.83 | 6.54 | 0.171527 | 0.152905 |
| 7.34 | 9.38 | 0.13624 | 0.10661 |
| 9.12 | 11.71 | 0.109649 | 0.085397 |
![Lineweaver Burk Plot = 1.203x0.061 R=0.997 NT TIITTO 0.2 0.4 0.6 0.8 1/[S]](http://img.homeworklib.com/questions/57f6ddc0-cdb2-11eb-a88f-1ffa1f09f5fd.png?x-oss-process=image/resize,w_560)
Comparing with the equation in the plot the standard equation
1/Km = 0.061
=> Km =16.39
Km/Vmax = 1.203
=> Vmax=16.39/1.203
=> Vmax = 13.62 nM/s
Hanes Woolf:
Equation

| V | S | S/V |
| 1.1 | 1.25 | 1.136364 |
| 4.15 | 3.6 | 0.86747 |
| 6.54 | 5.83 | 0.891437 |
| 9.38 | 7.34 | 0.782516 |
| 11.71 | 9.12 | 0.778822 |
![Hanes Woolf Plot y=-0.041x1118 R = 0.789 NIS) O 2 4 6 8 10 [s]](http://img.homeworklib.com/questions/589f2e20-cdb2-11eb-99e5-4906151ad373.png?x-oss-process=image/resize,w_560)
Comparing the equation in the plot with the standard equation
1/Vmax=0.041
=>Vmax= 24.39 nM/s
Km/Vmax = 1.118
=> Km = 24.39*1.118
=>Km=27.268
Eadie Hofstee:
Equation:

| S | V/S | V |
| 1.25 | 0.88 | 1.1 |
| 3.6 | 1.152778 | 4.15 |
| 5.83 | 1.121784 | 6.54 |
| 7.34 | 1.277929 | 9.38 |
| 9.12 | 1.283991 | 11.71 |
![Eadie Hofstee Plot y= 23.37x20.14 R2 = 0.840 0 0.2 0.4 0.6 1 1.2 1.4 0.8 v/[S]](http://img.homeworklib.com/questions/594930f0-cdb2-11eb-a2c3-e95f6bb23fa2.png?x-oss-process=image/resize,w_560)
Comparing with the equation in the plot the standard equation
Vmax= 20.14 nM/s
Km= 23.37
Summary of all answer:
| Lineweaver Burk | Hanes Woolf | Eadie Hofstee | |
| Vmax | 13.62 | 24.39 | 20.14 |
| Km | 16.39 | 27.268 | 23.37 |
Use the values from Table 13 to generate a Table showing 1/[S]
and 1/V Plot Lineweaver Burke (1/v vs. 1/[s]) and caculate Km and
Vmax in the absence and presence of 1mM inhibitor A. What is the
nature of inhibitor A?
Plot 1/V vs 1/[S], and caculate the values of Km and Vmax in the
absence and presence of 3 mM and 5mM of inhibitor B. What is the
nature of inhibitor B?
Plot 1/V vs [I] i .e Dixon...