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A box of m = 50 kg is on an inclined plane with θ = 22 degrees. You are exerting a force of 100 N parallel to the plane and up the plane as shown. If the box is at rest and the coefficient of static friction between the box and the surface of the plane is 0.4, what is the force due to static friction on the box? 182 N 84 N 284 N 100 N OON

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Answer #1

10g F= 100N = 10), 100 N

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