3. Given the zeros are x = -2, x = 4 and x = 7
Therefore, (x + 2), (x - 4) and (x - 7) are the factors of f(x)
Thus,
f(x) = a(x + 2)(x - 4)(x - 7)
Let us assume the leading coefficient is 1 i.e,. a = 1
Therefore,
f(x) = (x + 2)(x - 4)(x - 7)
The degree of the function f(x) is 3 i.e. odd and the leading coefficient is 1 i.e. positive
Therefore,
As x -> +
, f(x) -> +
As x -> -
, f(x) -> -
4. f(x) = - x6
The degree of the function f(x) is 6 i.e. even and the leading coefficient is -1 i.e. negative
Therefore, the end behavior is as below:
As x -> +
, f(x) -> -
As x -> -
, f(x) -> -
5. f(x) = 5x3 + 8x7
The degree of the function f(x) is 7 i.e. odd and the leading coefficient is 8 i.e. positive
Therefore, the end behavior is as below:
As x -> +
, f(x) -> +
As x -> -
, f(x) -> -
Question 3 Create a polynomial which has the following zeros: x = -2,4,7. Explain the behavior...
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