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If the probability that a couple produces a girl is 0.89381, and if the couple has...

If the probability that a couple produces a girl is 0.89381, and if the couple has 7 children, what is the probability they will have: 4 boy(s) and 3 girl(s) (in any order)? Please include work! When I did the problem I got 1.83 but that doesn't seem right.

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Answer #1

here this is binomial distribution with p=0.89381 and n=7

tehrefore probability of 3 girls =P(X=3) =\binom{7}{3}(0.89381)^{3}(1-0.89381)^{4} =0.003178

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