Question

Problem 2. (Do not solve part b) (20 points) a. Interpolate at x = 0.75 using the second-degree Lagrange interpolating polynomial.

Answer 1

`Hey,

Note: If you have any queries related the answer please do comment. I would be very happy to resolve all your queries.

clc
clear all
close all
format long
x=[0,0.5,1];
y=sin(x);
disp('y at x=0.75 is')
[yv]=lagrangeInterp(x,y,0.75)
function [yhat]=lagrangeInterp(x,y,interpx)

X=x;
f=y;
x=interpx;

l=0;
for i=1:length(X)
li=1;
for j=1:length(X)
if i~=j
li=(li).*((x-X(j))/(X(i)-X(j)));
end
end
l=(l)+((li)*f(i));
end
yhat=l;
  
end

- O X Pradeep do E C . Search Documentation MATLAB R2018a HOME + G New Open Save PLOTS C Find Files 3 Compare - Print D Run Section 8 APPS EDITOR PUBLISH VIEW Insert E fx EH - Go To - Comment % %% Breakpoints Run Run and Advance Run and Find Indent 1 - 6 Advance Time NAVIGATE EDIT BREAKPOINTS PRADEEP KALRA Documents MATLAB O Editor - C:\Users\PRADEEP KALRA\Documents\MATLAB\saveee.m +1 saveee. mx bisectionmethodbypradeep.m x eulerSystem. m RUN C: Users ох x googleLinks. m x HomeworkLib2.m x testc. m x ahk. m x nse_filt. m x + FILE a Current Folder Name - codegen convertFinal directory1 example first googleLinks mathlab mynewdir X=x; f=y; x=interpx; 1=0; New folder questions old simple_gui2 for i=1:length (X) li=1; for j=1:length(X) if i =j li=(li).*((x-x(j))/(x(i)-x(j))); end end 1=(1)+((li) *f(i)); end yhat=l; 1.png 2.png 3.png Details Workspace Name Lend Value [0,0.5000,1] [0,0.4794,0.8415) 0.6751 Ну Шуу Command Window y at x=0.75 is y = 0.675120773256113 fx >> lagrangelnterp g a Type here to search In 27 Col 4 ENG 5:58 AM IN 04/18/20 ola ()

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