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An electron (charge -1.6 x 10^-19 C) moves on a pa
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Answer #1

charge q= -1.6 X 10^-19 C

Electric field = E = 3 N/C

Force F on electron = qE = -4.8 x 10^-19 Newtons

Distance moved = s= 15 cm = 0.15 m

We have,

Work done = Fscosθ

= 4.8 x 10^-19 x 0.15 x cos(90) (as the path of electron is perpendicular to the force on it)

= 0

Therefore Work Done on electron is 0

Option D is correct

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