The activation energy for the decomposition of hydrogen iodide is found to be 180 kJ mol–1 and the rate constant for this reaction is reported to be 0.24 mol–1 L min–1at 540 °C. What is k for this reaction at 30 °C?
ln(k2/k1) = Ea/R[1/T1 - 1/T2]
K1 = ? T1 = 30 c = 303 k
K2 = 0.24 T2 = 540 c = 813 k
Ea = 180 kj/mol , R = 8.314 j.k-1.mol-1
ln(0.24/k1) = (180*10^3/8.314)((1/303)-(1/813))
K1 = rate constant at 30 c = 8.2*10^-21
The activation energy for the decomposition of hydrogen iodide is found to be 180 kJ mol–1...
Calculate the activation energy for the decomposition of
hydrogen iodide (HI), if at 573K the rate constant is 2.91E-6 M/s;
and at 773K the rate constant is 7.65E-2 M/s.
Note: answer should be 187.38 kJ/mol
Calculate the activation energy for the decomposition of hydrogen iodide (HI), if at 573 °K the rate constant is 2.91 x 106 M/s; and at 773 "K the rate constant is 7.65 x 102 M/s. a. -1.41 kJ/mol b. 187.38 kJ/mol c. 10.18 kJ/mol d....
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