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A sample of V weighs 31.5 grams. Will a sample of Na that contains the same number of atoms weigh more or less than 31.5 gram
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Homil moss of V=50-94154 ond Na - 22.9890 50 9415 9 of u has 6.022x10 23 atoms (according to mole and Avagadro number of arom22.9899 of Na has 6.022x 1023 atoms i. 29 of Na has 3.723 x 1023 atoms 2. 3.723x1013x 22.989 = 1422 59 of Na has 6:022 X 2013

From the calculations seen in both the image, we see that, 14.212 g of Na is having same number of atoms as that of 31.5 g of V.

Thus, the sample of Na that contains same number of atoms weigh less than 31.5 g of V that has same number of atoms.

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