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What is ∆Grxn at 25ºC for the following reaction: 4Au3+(aq, 0.050 M) + 12OH–(aq, 0.0020 M) --> 4Au(s) + 3O2(g, 0.15 atm) + 6H2O(l)? Given the following standard reduction potentials: Au3+(aq) + 3e– --> Au(s); Eº = 1.40 V O2(g) + 2H2O(l) + 4e– --> 4OH–(aq); Eº = 0.401 VQuestion 5 0 / 1 point What is DGrxn at 25°C for the following reaction: 4Au3+(aq, 0.050 M) + 120H(aq, 0.0020 M) --> 4Au(s)

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Answer #1

Au 3+ & 300 - Aucs) - 0 E = t.4oy 40H ③ O2 + 2H2O +uco - E = -0.401 v Net Reaction - 4 x EqC) + 3x Eq (2) 4 Au 3+ (aq) + 12 o

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