A chemist requires 0.409 mol Na2Co3 for a reaction.
How many grams does this correspond to?

Molar mass of Na2CO3 = 106 g/mole
Calculate the mass of Na2CO3 as follows:
Mass = moles * molar mass
Mas = 0.409 * 106
Mass = 43.354 gram.
Therefore, answer is 43.354.
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