Homework Answers
The arrhenius equation is
ln(K2/k1) = Ea/R[1/T1 - 1/T2]
From exeriments 1 and 2,
K2 = 7.70*10^-13 cm^3/molecule* s, T2 = 258 k
K1 = 5.90*10^-13 cm^3/molecule* s, T1 = 238 k
Ea = x j/mol , R = 8.314*10^-3 kj.k-1.mol-1
ln(7.70*10^-13/5.90*10^-13) = ((x)/(8.314))((1/238)-(1/258))
x = 6796.6 J
Ea = activation energy of the reaction = 6796.6 J/mol
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