Question

Consider the following cell: Ni(s) | Ni2+(aq, 1.00 M) || Cl(aq, ? M) | Cl2(g, (5.100x10^-1) atm) Pt(s) For this cell, E° = +1
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Nil Ni2+ (as IM) 11 cicas, am) 12 (9, s. 1810 at x loatin) Als et concentration of cê ion be x M NiN; 2 + (aq, IM) 11 cé caq,R = 8.314 J K moe T = 25%= 298K F = 96500 C na No. of é exchanged in reaction. Eren = E cell - 0.059 log [Ni²+] Pch =

Add a comment
Know the answer?
Add Answer to:
Consider the following cell: Ni(s) | Ni2+(aq, 1.00 M) || Cl(aq, ? M) | Cl2(g, (5.100x10^-1)...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq)...

    Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq) (1.50 M) | Ni(s) Zn 2+ (aq)/Zn (s) E o = - 0.760 V Ni2+ (aq)/Ni (s) E o = - 0.230 V a) Sketch the voltaic cell represented with the above line notation. Label the anode and cathode and indicate the half-reactions occurring at each electrode and the species present in each solution. Also indicate the direction of electron flow (3 marks). b)...

  • A voltaic cell is constructed from an Ni2+ (aq) -Ni(s) half-cell and an Ag+ (aq)- Ag(s)...

    A voltaic cell is constructed from an Ni2+ (aq) -Ni(s) half-cell and an Ag+ (aq)- Ag(s) half-cell. The initial concentration of Ni2+ (aq) in the Ni2+ - Ni half-cell is [Ni2+1 = 1.80x10-2 M. The initial cell voltage is +1.13 V. Part A By using data in Table 20.1 in the textbook, calculate the standard emf of this voltaic cell. V AEQ ? E V Submit Request Answer Part B. Will the concentration of Ni2+ (aq) increase or decrease as...

  • For the following electrochemical cell: Fe(s)| Fe3+(aq) || Cl(aq) | Cl2(g)|| Pt(s) a) Write the Cell...

    For the following electrochemical cell: Fe(s)| Fe3+(aq) || Cl(aq) | Cl2(g)|| Pt(s) a) Write the Cell Reaction for this Cell. b) Identify the Anode and Cathode.

  • Question 2. [10 Marks] Given the following half-cell reduction potentials: Ni2+ (aq) + 2e-F Ni(s), Ered...

    Question 2. [10 Marks] Given the following half-cell reduction potentials: Ni2+ (aq) + 2e-F Ni(s), Ered = -0.23 V Pt2+ (aq) + 2e-E Pt(s), Ered = +1.2 V Pd2+(aq) + 2e- EPd(s), Ered = 0.99 V a) Sketch the cell for which the overall cell potential is the greatest. [3 Marks) b) Identify the cathode and anode, and then show the direction of electron flow for the cell in the circuit (a). [3 Marks] c) Will Pt(s) reduce Pd2+(aq)? Explain...

  • 6. Consider a voltaic cell based on the following cell reaction: Ni(s) + At2(s) ? Ni2+(aq)...

    6. Consider a voltaic cell based on the following cell reaction: Ni(s) + At2(s) ? Ni2+(aq) + 2At– (aq) Given that the standard cell emf is 0.55 V, what is the standard reduction potential for astatine? [E°(Ni2+/Ni) = –0.25 V]

  • A galvanic cell using Ni2+(aq) / Ni(s) half-cell and Hg22+(aq) / Hg(l) half-cell is prepared. The...

    A galvanic cell using Ni2+(aq) / Ni(s) half-cell and Hg22+(aq) / Hg(l) half-cell is prepared. The E°nickel = -0.25 V and E°mercury = 0.789 V. (blank 1) Write the balanced reaction that occurs at the anode. (blank 2) Write the balanced reaction that occurs at the cathode. (blank 3) Calculate the standard cell potential of this galvanic cell. (blank 4) Write the shorthand cell notation for the galvanic cell. Question 10 options: Blank # 1 Blank # 2 Blank #...

  • Consider the following electrochemical cell (battery): Mg(s) │ Mg2+(aq) ║ Cl- (aq) │ Cl2 (g) │...

    Consider the following electrochemical cell (battery): Mg(s) │ Mg2+(aq) ║ Cl- (aq) │ Cl2 (g) │ Pt(s) all gases 1 atm, all solutions 1.0 M a. Write the respective reduction half-reactions occurring on each side of the salt bridg, and from some reference, get the half-cell potential (in volts) for each. b. Determine what reaction occurs overall, and calculate the Eo cell for this electrochemical cell. c. Make a drawing of this cell, and label the ANODE and the CATHODE....

  • Question 4 A galvanic cell uses the reaction: 2Ag+(aq) + Ni(s) --> 2Ag(s) + Ni2+(aq) a)...

    Question 4 A galvanic cell uses the reaction: 2Ag+(aq) + Ni(s) --> 2Ag(s) + Ni2+(aq) a) calculate the Standard Cell Potential (Ecell) of this galvanic cell and b) which metal is the cathode? a) 1.03 V; b) nickel a) 1.03 V; b) silver oooo a) 0.57 V; b) nickel a) 0.57V; b) silver

  • Consider the following cell diagram: Pt(s) | Fe3+(aq) , Fe2+(aq) || Cl–(aq) | Cl2(g) | Pt(s)...

    Consider the following cell diagram: Pt(s) | Fe3+(aq) , Fe2+(aq) || Cl–(aq) | Cl2(g) | Pt(s) The reaction utilized by this cell is Question 8 options: Fe2+(aq) + 2Cl–(aq) --> Fe(s) + Cl2(g) Fe(s) + Cl2(g) --> Fe2+(aq) + 2Cl–(aq) 2Fe3+(aq) + 2Cl–(aq) --> 2Fe2+(aq) + Cl2(g) Fe3+(aq) + Cl–(aq) --> Fe2+(aq) + 1/2Cl2(g) 2Fe2+(aq) + Cl2(g) --> 2Fe3+(aq) + 2Cl–(aq)

  • Consider the following half-reactions: Half-reaction E° (V) Cl2(g) + 2e - →2Cl(aq) 1.360V Ni2+(aq) + 2e...

    Consider the following half-reactions: Half-reaction E° (V) Cl2(g) + 2e - →2Cl(aq) 1.360V Ni2+(aq) + 2e Ni(s) -0.250V Mg- (aq) + 2e → Mg(s) -2.370v (1) The weakest oxidizing agent is: enter formula (2) The strongest reducing agent is: (3) The strongest oxidizing agent is: (4) The weakest reducing agent is: (5) Will Cl(aq) reduce Mg2+(aq) to Mg(s)? (6) Which species can be reduced by Ni(s)? If none, leave box blank.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT