Question

If 400 mL of some Pb(NO3)2 solution is mixed with 400 mL of 1.10 x 10-2 M NaCl solution, what is the maximum concentration of the Pb(NO3)2 solution added if no solid PbCl2 forms? (Assume Ksp = 2.00 x 10-5 M at this temperature.) Enter the concentration in M. Submit Answer Tries 0/99

Answer 1

1: Let, the maximum concentration of the pb (NO) Solution added if no solid pbely forms is x(m). Now, according to your given question Hooml of x (M) Pb(NO3)2 solution is mixed with 400ml of 1.10X10–2M Nael solution Now, using the general formula, Tvis, = V2 S2 for Pb(NO3)2, 400 X X = 800 xl Spb(nog), Where, r, s, initial s final volume respectively .. (Spoesia), = siue a = 4x (m) for Naelo 400 X 1-10 x1032 = 800 xSelo) 400 x 1.20 x 10-2 800 - Scanned with CamScanner 1.10 X10-2: 3:55 x102()

. In a tollows, solution phela dissociates as follows... pbela phat it 2e- Here, [pb2" ] = {x(m) [«] =:55 x102(M) .: Solubility product, Ksp = [Pb2+ ] [41] = 2.00 X 1065 = 12 *(55 x1052) 2.00 X 10 -5 = X X:302 x 10-4 2x 2000 x10-5 .302 x 10-4 = 1.324 (M) So, the maximum concentration of the solution added if no solid phela forms ds Scami: 32(m) fins ] pb(NO2) is
Note: when the solubility product and the ionic product is same, there no precipitation will occur.