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Calculate the OH and the pH of a solution with an (H] = 1.1 x 10-8 M at 25 °C. [OH-] = pH = Calculate the (H+) and the pH of

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At 25°c (H+) (OH-] = kw : 10-14 - - pH = -log (H+] poH = -log COH-] and [ht] = 10-14 [OH-] [OH-] = 10-14 CH+] (H+) - 10-ÞH pH

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