Question

Calculate the wavelengths (nm) of the lines in the Balmer Series from the values of ninitial and nfinal using equations (4) and (2) presented in your lab. Show one sample calculation for line 1 (Balmer-a) in your lab notebook, and enter the values in the table below (whole numbers only, except for column 4, use 3 sig figs). The spectral lines are grouped into series according to n'. Lines are named sequentially starting from the longest wavelength/lowest frequency of the series, using Greek letters within each series. For example, the 2 1 line is called "Lyman- alpha" (Ly-a), while the 6-3 line is called "Paschen-delta" (Pa-7). Line Wavelength (nm) 1 (Balmer-a) 2 (Balmer-8) 3 (Balmer-7) 4 (Balmer-8)

Answer 1

Dear student,

Ans. for Balmer series electron Tumps from energy level n=3 to n=2. 1o Balmer-a ni = 3 , ne=2 4-9 . :36 - for ware length, where x = warnelength R = Rydberg constant = 1.097 x 107mt ne = 3 nf =2

: 1-очах то? ( ) mi n =) . 1. Сээ х 10"х — У), 2 А - -7 3 1. 095 х х = С. 6хот А - So 6 мм 2. Bog muЯ - В h; - , - 2- - - 3

32 52 54 -1* Now, for wavelength z 1.099 X 107 ha -1,)mt ALE 1,097 x 10.7x21 my 100 09 = 1oo x 10-7 m 1.097x21 À = 4 34 X 107 x = 434 nm 4. Balmers ni = 6 ing =2 -

Now, for wavelength - 1099 X 10*a ( the ) mi = 1.097 x 107 x m/ on 1 - 9 x 10-7 m 1.097.82 x = 4.10 x 10 7m - x = 410 nm,

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