Question

Iron metal reacts with chlorine gas according to the equation:

2Fe(s) + 3Cl2(g)  2FeCl3(s) If 35.0 g each of iron and chlorine react, how much FeCl3 will be formed?

Answer 1

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SOLUTION The given chemical reaction is d at 2 fe is + 30 (9) - 2 reclz is Mass of fe taken = 35.09 est Moles of re taken & 35. Ormoles 8. 56 = 0.625 moles Mass of Cle taken - 350g Moles of a taken - 350 moles . 0.98 moles Iron will act as a limiting reagent in the above reactionſ since moles of ke & moles of a ? Moles of Iron will be totally converted to Fell Using stoichiometry of reaction we can say, I mole of fe forms 2 moles of Fell o 0-625 moles of Fe forms 0.625 moles of Fell An Total felly formed = 0.625 moles ox 101.56 g

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