The equilibrium constant, Kp, for the following reaction is 55.6 at 698 K. H2(g) + I2(g)...

Question

Question

The equilibrium constant, Kp, for the following reaction is 55.6 at 698 K.

H2(g) + I2(g) 2HI(g) If ΔH° for this reaction is -10.4 kJ,

what is the value of Kp at 577 K?

Kp =

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Answer 1

Answer #1

kp at 6.98 K = 55.6 DA- - 14 3. So kp at 577K. M प H₂ + Iz 2 HI By the equation AH १.30 १५ (7 - (०.५ 2 .303X8.3) UP 56 7 69

Answer 2

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