Question

hello, i dont know if i have done my mass specturm and ir sepctrum worksheet correctly. Does it look right? thank you for all ur help!

47,09 +6.59 53.68 100-53,68=46.32% remaining due to Oxygen 89.09. He = 12.011 H=2.94 of 15,944 c=47.09% 89.09 -2.98=3 301026. gtmol - t = 6.59% 5 CIH201 C3H603 C289.098.4709=41.95 g 47.09% x 89.09 anol Imol = 3.49 mol noles c-c 100 ma compeha 12.olg . saoaghel & Imolt -5,81 mol TOO ^ malcomp hola- 90 - 88. Il compd-C47.04C+ 6.54H)=3*.45go 34.4540 -= 2.15 amol C=47.09 4. H=6.591 0 = 46.321. 16.00g Divide by respective nol. wt. (2C+2)+N-(H+x) = 47,09% 6.59% 46.324. C31603 12.0107 1.007 16 (2+3+2)+0-(6+0) - = 3.92 = 6.54 = 2.89 Divide by lowest invegers (8)-16) - = 3,92 6.54 = 2.89 1232.84 2 ,89 2.84 I degree of unsatu.ch & the corpd could be Empherical for mula CLASH 2.60 CH10 2 x 200 12,011= 1x1s.aag after 1:2:1 CIH2O1 an alkene or - a municyclic 2 1 . C la

Answer 1

The structure of the compounel is :- CHy =CH-CH2-ce 3- Chloro prob-l-ene. Mal weight given = 89.09 g/mol But mass spectrum shows m/z value 76. Molecular weight given is wrong.. 0% of Carbon :- 47.09% % of Hydrogen :- 6.59% mt $ m+2 peaks are at ratio 1:3. Do ce atom must be present. 0% of ce atom :- (100.00 - 47,09 - 6.59)% → 46. 32%. So C = 47.09% H= 6.59% Cl = 46.32% Divide each atoms by their atomic weights. c= 47.09 Ha 6.50 cd=46.32 ! 12

C = 3.92 H = 6.59 Cl = 1.30 Now, clivide all emswers with lowest mowers C = 3.92 1.30 H=6.59 1.30 cl = 1.30 1.30 c=3 H-5 ce=1.. So molecular formula of compound is B C₂ ts ce Degree of unsaturaturation → No. of carbons - No. of Hydrogens 2 - No. of Halogens +1 1. Thus 3 - 5x1 - 1 x1 + 1 = I. Degree of in saturation = 1 one double bond or mono cyclic.

Description of IR data:- = C-H stretch - 3100 cm , strong $ . Shaop. - C-H (553) stretch -> 2900 -- 2950cm/ strong $ Shao ß. -c c stretch 1550-1650cml, strong $ Shes b. -c-ce stretch 750-720 cmt strong & sharp. These are the expected values of main Jeaks. Description of mass spectroscopy data :- CH2 = CH – CH2-Ce -le-CH2=CH-CH2 Toer - le m/2=76 m/2 at 78 due to 37c_isotope. Peak ratio: 76: 78 3:1 Plz don't dislike CH₂=CH-ci m/2 = 4-1
The IR data and mass spectroscopy data solution done by you are correct. Answer is also correct. Well Done.