Homework Answers
Calculation of Cs :
Material is solid till E2
E2 = 836J T2 = Tfusion = 239°C
E1 = 167J T1 = 47.7°C
We know a relationship between Heat dissipated and specific heat of material
E2 - E1 = mCs(T2 - T1)
Given, m = 9.80g
836 - 167 = 9.8*Cs(239 - 47.7)
Cs = 0.36 J/g °C
Calculation for CL :
Material is liquid between E3 and E4
E4 = 2890J T4 = 485°C
E3 = 1410J T3 = 239°C
m=9.80g
E4 - E3 = mCL(T4 - T3)
2890 - 1410 = 9.8*CL (485 - 239)
CL = 0.61 J/g °C
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