Review Problem 16.065 A sodium hydroxide solution is prepared by dissolving 9.0 g NaOH in 3.00...

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Question

Review Problem 16.065 A sodium hydroxide solution is prepared by dissolving 9.0 g NaOH in 3.00 L of solution. What is the mol

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Answer 1

Answer #1

ANSWERS-

9 gm of NaOH is added to 3L water,

Molarity = moles/volume

Moles of NaOH= mass / molar mass = 9/40 = 0.225 moles

NaOH = Na+ + OH-

As 1 mole NaOH gives 1 mole OH- thus 0.225 moles NaOH gives 0.225 moles of OH-

Molarity of OH- = 0.225/3 = 0.075 M

p[OH] = -log(OH-) = -log(0.075) = 1.125

pH = 14-pOH = 14-1.125 = 12.875

and as [OH-] × [H+] = 10^-14,

thus, [H+] = 1.333 × 10^-13

Answer 2

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