Question

The standard enthalpy change for the following reaction is -774 kJ at 298 K. Fe(s) + 5 C(s.graphite) + 5/2 O2(g) Fe(CO)(1) AH

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Answer #1

An extensive property is defined as the property that depends on the amount of matter involved.

Enthalpy is an extensive property.

The standard enthalpy of the reaction is as follows:

Fe(s) + 5C(s,graphite) + 5/2O2(g) \rightarrow Fe(CO)5(l) \Delta Ho = -774 kJ

If the amount of the matter is doubled, the enthalpy change value will be 2 times the initial enthalpy.

2Fe(s) + 10C(s,graphite) + 5O2(g) \rightarrow 2Fe(CO)5(l) \Delta Ho = -774 kJ x 2

Thus,

\DeltaHo = -774 kJ x 2

\DeltaHo = -1548 kJ Or -1550 kJ [3S.F]

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