Question

Briefly review the reagents involved in the procedures for test tubes #2 and 3 (see pp. 8-3 and 8-4 in your lab manual.). Each test tube started with a solution containing the sodium or potassium salt of each anion. In test tube 2, a solution of silver nitrate (AgNO3) was added. In test tube 3, a solution of barium chloride (Bach) was added. In both cases, we willinore the addition of nitric acid.) Refer to the solubility guidelines from the GKFBD textbook (pp. 170-171), and determine which anion compounds will form a precipitate upon the addition of silver nitrate (test tube 2) and barium chloride (test tube 3). In the table below, mark an 'X' in each box that corresponds to the formation of precipitate. [if you have your anion table from the lab with you, you can look at that as well; but you should use the solubility guidelines to determine which precipitates will form.) AgNO3 Balla AgNO3 Balla Anion Test Test Anion Test Test Compound Tube 2 Tube 3 Compound Tube 2 Tube 3 NaCH3COO Nal NazC03 NaNO3 NaF NaSCN NaCl Na2SO4 NaBr Na3PO4 2. For each precipitate formed above, write the appropriate net ionic equation. Phase labels and ion charges are required to receive full credit. First, write the reactions for test tube #2, then the reactions for test tube #3. Please show ONLY the net ionic equations here, use a separate sheet of scratch paper to work out the molecular and overall ionic equations if you wish. TEST TUBE 2 REACTIONS

Part 1- Could someone tell me which of these are soluble and insoluable.

Part 2- How do you write a net ionic equation for the precipitate?

Answer 1

Anion Compound	Test tube 2 (AgNO3)	Test tube 3 (BaCl2)	Overall molecular equation	Net ionic equation
NaCH3COO	CH3COOAg (soluble)	(CH3COO)2Ba (soluble)	NaCH3COO + AgNO3 = NaNO3 + CH3COOAg 2 NaCH3COO + BaCl2 = 2 NaCl + (CH3COO)2Ba	CH3COO- (aq) + Ag+ (aq) = CH3COOAg (s) 2 CH3COO- (aq) + Ba2+ (aq) = (CH3COO)2Ba (s)
Na2CO3	Ag2CO3 (insoluble)	BaCO3 (insoluble)	Na2CO3 + 2AgNO3 = 2 NaNO3 + Ag2CO3 Na2CO3 + BaCl2 = 2 NaCl + BaCO3	2Ag+ (aq) + CO32- (aq) = Ag2CO3 (s) Ba2+ (aq) + CO32-(aq) = BaCO3 (s)
NaF	AgF (soluble)	BaF2 (insoluble)	NaF + AgNO3 = NaNO3 + AgF 2NaF + BaCl2 = 2NaCl + BaF2	Ag+(aq) + F- (aq) = AgF (s) Ba2+ (aq) + 2F- (aq) = BaF2 (s)
NaCl	AgCl (insoluble)	No precipitate	NaCl + AgNO3 = NaNO3 + AgCl 2NaCl + BaCl2 = No reaction	Ag+(aq) + Cl- (aq) = AgCl (s)
NaBr	AgBr (insoluble)	BaBr2 (soluble)	NaBr + AgNO3 = NaNO3 + AgBr 2 NaBr + BaCl2 = 2 NaCl + BaBr2	Ag+(aq) + Br- (aq) = AgBr (s) Ba2+ (aq) + 2Br- (aq) = BaBr2 (s)
NaI	AgI (insoluble)	BaI2 (soluble)	NaI + AgNO3 = NaNO3 + AgI 2 NaI + BaCl2 = 2 NaCl + BaI2	Ag+(aq) + I- (aq) = AgI (s) Ba2+ (aq) + 2 I- (aq) = BaI2 (s)
NaNO3	No precipitate	Ba(NO3)2 (soluble)	NaNO3 + AgNO3 = No reaction 2 NaNO3 + BaCl2 = 2 NaCl + Ba(NO3)2	Ba2+ (aq) + 2NO3- (aq) = Ba(NO3)2 (s)
NaSCN	AgSCN (insoluble)	BaSCN (soluble)	NaSCN + AgNO3 = NaNO3 + AgSCN 2 NaSCN + BaCl2 = 2 NaCl + BaSCN	Ag+ (aq) + SCN- (aq) = AgSCN (s) Ba2+ (aq) + 2 SCN- (aq) = BaSCN (s)
Na2SO4	Ag2SO4 (insoluble)	BaSO4 (insoluble)	Na2SO4 + 2AgNO3 = 2NaNO3 + Ag2SO4 Na2SO4 + BaCl2 = 2 NaCl + BaSO4	2Ag+(aq) + SO42- (aq) = Ag2SO4 (s) Ba2+(aq) + SO42- (aq) = BaSO4 (s)
Na3PO4	Ag3PO4 (insoluble)	Ba3(PO4)2 (insoluble)	Na3PO4 + 3AgNO3 = 3NaNO3 + Ag3PO4 2Na3PO4 + 3BaCl2 = 6 NaCl + 2Ba3(PO4)2	3Ag+ (aq) + PO43- (aq) = Ag3PO4 (s) 3Ba2+ (aq) + PO43- (aq) = 2Ba3(PO4)2 (s)