Question

Question 4 5 pts What mass (in grams) of C3Hg is required to fill an 18.9 L container at a pressure of 111 psi at 25.3 °C? O 0.132 257 O 2.54 O 3.03 x 10^3

Answer 1

14) The right answer is option [B], 257. Explanation We will use the gas equation to solve this PV = nRT where, P = pressure of gas, v= volume na moles of gas, R= universal gas constant T= Temperature Given, For P=1lipsi C3H8. We will convert this P from psi to ahm . Ipsi = 0.068 atm. So, Il psi = (111X0.068) ahm = 7:55 31 ahm. volume of C3Hz = 18.9L R = 0.082057 Lahm Temperature (T) = 25.3°C +273k = 298.3k Substituting all the values in the ideal gas equation , we get 'n' of C3H8

... mores (n) = P XV RAT - 7.5531 ahm x 18.9% 0.082057 X alm x 298.34 . mol. K = 5.828 . Now to get the mass (9) of Castle we need to convert the moles of CzHg to mass. Moles & Mass Molar Mass (Mulov Maas a Hg - 44° | 8 |mart ) .: Mass (9) - Moles & Molar Mass a = 5.828 X 44.1 mor mor = 257.01g. Mass of C3H8 or, 257 g (rounded to whole no) Aus Our answer corresponds to ophon B]