Question

A(g)⇌B(g)+C(g) Find the equilibrium concentrations of A, B, and C for each of the following different values of Kc. Assume that the initial concentration of A in each case is 1.0 M and that the reaction mixture initially contains no products. Make any appropriate simplifying assumptions.

Kc= 2.0

Kc=Kc= 1.6×10⁻²

Kc=Kc= 1.6×10⁻⁵

Answer 1

А) - В'Я? * 1.OM + НО ПО + tu + – № E (1.0-W) M NM x M к. - - CB][C] [А] - (1.0 - 3) б) к = 20 х = 2.0 1.o- * + 2.0 - 2.0 = 0 = 0.132 At equillibrium, сдаа 10 — 0.132 - о. 268 м Э Св] - [С] = 0.732 м

il Kc = 1.68102 1.6x102 = x² 1.0-a x² + (1.6x10²) - 1.68100 =0 2 -0.1187 in At equillisium 0.8913 M. [A] = 1.0 -0.1187 = [B] = [C] = 0.1187 M uni) Kc = 1.68105 1.6*105 = x 10-2 x²+ (1.6x10s) - (1.68105)=0 a= 0.00399 TB] = [C] = 0.00399 M CA] = 1.0 -0.00399 = 0.996 M