Approximate the concentration of OH in a 0.40 M solution of NHą (K = 1.8x10-5), as...

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Question

Approximate the concentration of OH in a 0.40 M solution of NHą (K = 1.8x10-5), as shown in the reaction below. NH3(aq) + H20

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Answer 1

Answer #1

NH3(aq) + H2Ole) = NHy+ + OH (aq) 0.40M Hyu 4x -x Ell 0.40-2 Kb = [Nhat] lor] (NH3] 1.8x105 = ? 0.40-X. 0.4 >> X , so neglec

Answer 2

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