Question

Question 26 of 31 Sub How many moles of HCl need to be added to 200.0 mL of a 0.200 M solution of Naf to make a buffer with a pH of 3.60? (ka for HF is 6.8 * 10-4) mol

Answer 1

Answer: HF - Hit HF = HT + EN NOR & Natt F Ka= 6.8x10-4 Hce role of NaF= 0.04 Ht is Cannury from the Im He & Heece p ot a Bulus Sahia. p"=pka + las [Cajupale Base] P = P + ley [Acid]

Deteren reele of NAF = 0.20 Mx 200 m Tooon - O.olimere 3.6= 3.17 + lap 10.04-2) lag lolote ) - 0.433 : 0.04-2 w = 2.71 0.04-2 = 2.712 0.04=2.71 2+2= 3.71 x=0.01018 more F- In this case the hot Protonate hare of F making HF so the formate amount will go down from 0.04 more and HF amount will go up from zero. to x= 0.01078 more of tt Produce and this is sen till more react | Hel role = 0.0/078mor

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