Question

Weignto comes9423 weight of beaker & alum 972.2313 Caleulations Dare 3-30-20 section - 2. Weight of alum crystals collect 2 ALO2 og beint of bener 164309 1.789g weight of beakertal 0 865. alig 3. Equations representing the synthesis Write below equations 1, 2, and 3 given in the text (+2KOH lag) HOH₂O 2kg + 2Al(OH)4 + 3H2198 32nrag)+ ZAILOH) ülaa)+4H250ulag) 2Kt Loa) +241 lagt 3 tlac) +A1312029100) #210-> AS042 4. Mole relationships from equations Fill in the blanks from the coefficients of the balanced equations ->2002A1456WD 240-> KA1130420 24,015) Corum) moles Al form _moles AMON).(aq) moles Al(OH)2(aq) form moles Ailla) mole Al" (ag) forms mole KAISO), 121,0 From the above you should be able to see that Each mole of Al metal forms mole alum Calculate the number of moles of aluminum metal you started with. The atomic weight of aluminum is g/mole. 9 H -> M ies A 6. From question 4, you saw that each mole of Al forms moles alum. Therefore, how many moles of alum could theoretically be produced from the moles of aluminum you actually started with? moves Al -> Moles Alum 7. Calculate from the answer to question 6 the weight of alum which could theoretically be produced. the molar mass of alum, KAl(SO4)2-12H20, is g/mole. Moles Aum-> Alum tunawo Theoretical % Wei 8. Calculate your percent yield of alum, using the formula given in Part 1 of this experiment 89 actualueild theoretical X 100 yeild

can I please get help solving number 4

Answer 1

Ans 4 . From the coeficients of the balanced chemical equations we can easily fill the blanks as follows:-

(a) 2 moles of Al form 2 moles of Al(OH​​​​​​​​4)-

(b) 2 moles of Al(OH​​​​​4​) - form 2 moles of Al​​​​​3+

(c) 1 mole of Al​​​​​3+ form 1 mole of KAl(SO​​​​​4 )2 .12H2O

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