Question  part b and c please

part B

dT = Kf x m, where d = delta (change), Kf is the freezing point depression constant, and m = molality.

[0-(-2.35)]oC = 1.86 oC/m x m

m = 2.35 oC / 1.86 oC/m = 1.263 molal

part C

dT = Kb x m, where d = delta (change), Kb is the boiling point elevation constant, and m = molality.

[102.56-100.00] oC = 0.512 oC/m x m

m = 2.56 oC / 0.512 C/m = 5.00 molal

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