Question

Balance the following half-reaction:
HONO→ NO₃^-

^{1. The first species to balance is the redox active species, the element that is changing oxidation state. In this reaction, the redox active species, N, is already balanced. 2. How many moles of H,O must there be on the reactant side of this half reaction? (Enter O if no moles of water are needed or enter #H2O where # moles of water are needed, e.g. if 4 moles of H20 are needed, type 4H20). Enter your answer in the box on the left. How many moles of H20 must there be on the product side of this half reaction? (Enter O if no moles of water are needed or enter #H20 where # moles of water are needed, e.g. if 4 moles of H,O are needed, type 4H20). Enter your answer in the box on the right. H2O + + HONO → + NO3- You are correct. Your receipt no. is 156-5637 Previous Tries 3. How many moles of protons must there be on the reactant side of this half reaction? (Enter O if no moles of H+ are needed or enter #H+ where # moles of H+ are needed, e.g. if 4 moles of Ht are needed, type 4H+). Enter your answer in the box on the left. How many moles of protons must there be on the product side of this half reaction? (Enter O if no moles of H+ are needed or enter #H+ where # moles of H+ are needed, e.g. if 4 moles of H+ are needed, type 4H+). Enter your answer in the box on the right. + H2O + HONO → 3H+ + + NO3- You are correct. Your receipt no. is 156-7027 Previous Tries 4. You now have mass balance but will need to balance charge. This will be done by adding electrons to the side of the reaction with excess positive charge. How many moles of electrons must there be on the reactant side of this half reaction? (Enter O if no moles of electrons are needed or enter #e where # moles of electrons are needed, e.g. if 4 moles of elecrons are needed, type 4e). Enter your answer in the box on the left. How many moles of electrons must there be on the product side of this half reaction? (Enter O if no moles of electrons are needed or enter #e where # moles of electrons are needed, e.g. if 4 moles of elecrons are needed, type 4e). Enter your answer in the box on the right. + H2O + HONO → + 3H+ + NO3-}

Answer 1

The balancing of equation is

balancing O

H2O + HONO ---------> NO3-

balancing H+

H2O + HONO ---------> NO3- + 3H+

balancing charge with electrons

H2O + HONO ----------> NO3- + 3H+ + 2e-

2moles of electrons are added to the product side only and none to reactant side to balance the charges.