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A buffer consists of 0.34 M NaH2PO4 and 0.28 M Na2HPO4. Given that the values for H3PO4 are, Ka1 -7.2 x 10-3 Ka2 = 6.3 x 10-8
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Answer #1

Hep 05 (aq) = HPOS (aq) + H+ (aq) 0.34M 0.28M Kal = 6.3x10-8 (as the two present species lies in 2nd equilibrium.) pKal= -log

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