Question 6 -- / 1 You wish to prepare a buffer containing CH3COOH with a pH...

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Question 6 -- / 1 You wish to prepare a buffer containing CH3COOH with a pH of 5.44. If the pka of acetic acid is 4.74, what

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Answer 1

Answer #1

Answer

1. 5.0

Explanation

Henderson - Hasselbalch equation is

pH = pKa + log([A^-]/[HA])

where,

A^- = conjucate base , CH3COO^-

HA = weak acid , CH3COOH

pKa = pKa of weak acid , 4.74

substituting the values

5.44 = 4.74 + log( [CH3COO^-]/[CH3COOH])

log([CH3COO^-]/[CH3COOH] = 0.70

[CH3COO^-]/[CH3COOH] = 5.0

Answer 2

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