Question

QUESTION 2 Kp = 6.51 at 800 °C for the ideal gas reaction: 2A(g) + B(g) 2 C(g) + D(9) 3.000 moles of A, 1.000 mole of B and 4.000 moles of C are placed in an 8000 cm rigid reaction vessel at 800 °C. What is the total pressure (atm) inside the vessel once equilibrium has been reached?

- Please use 273.15 when converting between Kelvin and Celsius temperatures.

- Use 96485 for Faraday Constant

- In problems that require fitting of a curve or straight line use linear regression. Do not use trend line. Sometimes the results can be different.

Answer 1

& A (s) + Bras Žorgt I (mol). Se F. Hot - Oy Ś . 3-dy uty 4+y 3-ey say Kp = (Pc) (P) ( Pajar Pp) = (Pr=nRT) P= nR I) 5) (MRT) (MART) in seg jø ( no RT) e ncomo c.mo a Фа*. Вт = Кр a (4+4) (x) Lv (3-8yx (1-4X RT

-) R = 0.0821 Leatm k.mo) T = 800c oy 1073K r = 8000 cm3 = 8 Litre 1. C. cm3= 1 mi) r -(1073)x 0-0821 1 - 8 = 11 6.51 = (1+y) y (3-QyjPci-yj* prit =) (6.51)(11) (3=238 C1-Y) = 4y + yupo => (71.61) (9743P_129)C1=Y) = 4y typ =7161 ( 9 - 3y + 4y42 490 – 12y+1242)= 4y+yo 5) 644.49 - 644.49€ + 0986.44 y 9 0986044403 -859.32 y + 855,32 ya? = 4y+ y 29 5) 0986.44 y 9 - 0985.44.99 9859-3239+48+644.487 +859.327-644.49 3) 986.444 Y - 1144.76 7+ 1507.81 ♡ -644.49 = 0 T =) only one real answer cusing online solver) Y = 6.94669 Holes of Y 6 no A = 3 - B = 1-4 C = 4+y D: y = 1.10676 = 0.05338 = 4.94662 = 0.94662

product at eg. Total moles off reactant and = Moles (A + B + C + D) = 7.05338 Total = (total) XRT T Call are ideal Gases) (Pr= Par PB + Pc + Pp) = (7105338) x 0.081 L.atm x 8073K Kimo) 8 L. 7.05338 X II P+= 77.58718 atm