Question

to know the 1. Calculate the pH for the following aqueous solutions containing Need A. 2.3 M HNO3 steps ph=-0. 36 B. (10 pts) 0.72M Ba(OH)2 Ph=141.16

Answer 1

Solution :

A) 2.3 M HNO3

HNO3 is dissociated as,

HNO3 === H+ + NO3-

2.3 M == 2.3 M --- 2.3 M

Thus, [H+] = 2.3 M

pH = - log [H+] = - log 2.3

pH = - 0.36

B) 0.72 M Ba(OH2

Ba(OH)2 === Ba2+ + 2OH-

0.72 M ==== 0.72 M --- 2 x 0.72 M

Thus,

[OH-] = 2 x 0.72 = 1.44

pOH = - log [OH-] = - log 1.44 = - 0.16

Since,

pH + pOH = 14

pH = 14 - pOH

pH = 14 - (-0.16) = 14 + 0.16 = 14.16