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Phosphoric acid: 85% in water (w/w)
(w/w means 85 g of phosphoric acid in 100 g of water)
Amount of solution used: 1ml
Molecular weight of phosphoric acid: 97.994 g/mol
Density of phosphoric acid: 1.88 g/ml
Mass of phosphoric acid used to make solution is: 85g
Therefore volume of phosohoric acid used is:
= 45.21 ml
Also as the density of water is 1 g/ml therefore volume of water used is 100 only
Hence, total volume of solution is: 100 ml water+ 45.21 ml phosohoric acid = 145.21 ml
No. of moles of phosohoric acid in 145.21 ml of solution is given by:
= 0.867 moles
No. of moles of phosphoric acid in 1 ml of solution is:
= 0.00597 moles
Therefore no. of mmoles of phosohoric acid in 1 ml solution is:
= 5.97 * 10-6 mmoles
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