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i want to verify my answer because i am not sure. i got 13.70932267 2 H2...


2 H2 (g) + O2 (g) — 2 H2O(g) Hydrogen gas and oxygen gas react to form water vapor as shown in the equation above. If 0.623 m

i want to verify my answer because i am not sure. i got 13.70932267
2 H2 (g) + O2 (g) — 2 H2O(g) Hydrogen gas and oxygen gas react to form water vapor as shown in the equation above. If 0.623 moles of hydrogen react with excess oxygen, how many moles of water will be created from the reaction?
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Answer #1

Given

2H2(g) + O2 (g)= 2 H2O(g)

According to the above balanced equation

2 moles of H2 reacts with excess of O2 to form 2 moles of H2O

Therefore 0.623 moles of H2 with excess of O2 will form = 2/2 X 0.623 moles of H2O

      = 0.623 moles of H2O

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