Question

In-Class Worksheet Carbohydrates Page 8 of 8 4. Label each molecule as containing an acetal, hemiacetal, neither, or both. Indicate if they are reducing or non-reducing sugars. CHO CH OH CH OH OH FO нон ону но осн, нон н -он К нон но -н нон CH,OH CH OH --O OH OH Онону он н Сньон он Снон н Кон н Со он нон он и 5. Show the product of treating the following molecule with B-glycosidase: 6. What are the similarities and differences between starch, cellulose, and glycogen? 7. Why does heparin act as a blood anticougulent? - 8. Why does chitosan make a fantastic band-aid? 9. How does a glucose test strip work? Why does it change color?

Answer 1

because it can on Hot Lot M OH It is open chain structure Casbohydrate. CHO ste neither herracetal po ketal Cardopento se ] (анонч теди аng ѕudаз ( "OH because of can be oxidised by either Tollens reagent (Ammoniacal. Agrity solution) of Fehling solution. (cusoython and ish dalt of citricalid), ChOH lierce et contain adenyde group. 6 Hof a on It's a hemi acetal - pH 7 because OR one of the bath Carbon contain oH group and alkoxy group ! in the ring structure. It'y reducing sugar il oxidise by Fehring solution of Tollens reagent. This is because in aqueous solution the homialetal can convert to open chain structure booming - CHo group, which can oxidise kay Tollens reagent.. choty I Op Chan no prevent they have on u ovom melon pt + Agde beth T (silver Ron bontpH berna on to bety a. I open it is buy mist) an acetal because one of or the Carbon et contain two alkoxy group. ( FOR .. 1 OR It ý not a reduling sugar , because bree it have no of group at anomeric (*) solution or Carbon, that can be used in basic aqueous solution to boom open chain structure by wyctrolysis of Qouth Tollens reagent No Rxn. 1207 pe If y neither homialetal nor ketal. ton ot ų a ketohexose contain a keto group. the But it is a reducing suar of Fehling solution -oh

The Ketonexose in the presence of basic oxidising agent (Tollens reagent of Fehling foration is converted into andohexose by rearrangement Hence it y reducing sugar though Contain Keto group. сон eH=0 Naot 1th 4 -os. Ho Hon (basin medium Ho AgNouton HH the on on (rearrangements hon COM L of shoothiton cooth CH ergost 3 WQVH a 4 ay an ale o Hop h to toh at the ch It ý an acetal because 20th both sing contain (XOR I OR HO BH ,OH no any of group. NO OH group is bree at the anomesic carbons Hence it y non reducing sugar, because aldehandle group can not be created in aqueous solution of in basic medium It ý both acetal and hemi acetal. (sing ) LOH Here sing A Contain no on * (ring A herniasretal Carbon and sing B contain aretal Cason (²). It ý a reducing sugas, because in aqueous solution (balio) the hemiacetal (ct present in sing A Converted to aldehyde group, which can oxidise. & ora Hoxha grey both acetal and hermi acetal o oh -TH Иe The ring A Contain hempacetal in33 singh and sing B contain acetal It can be oxidised bry carbon (at).. It reduling Pollery reagent. so sugar: it is a It contain free of group at ing A