Question

part 1

Based on their compositions and structures and on conjugate acid-base relationships arrange the bases shown below in order of increasing base strength from weakest to strongest base) О O POJ? OPOJ народ" ОНРО онгоцо нуро o HPO42 ОНРО O POZ. о народ" o Hypo4 o HPo4- ОРО, о народ ОНРО HPO 2 о Аво, олио, осоо со sou?- oso- - Asog Aso,? о мно- о сод" o s04- o Ако o AsOy соод o sou? o Ано NH окна NH2 NH2NH2

part 2 (please only show work and answer for part b)

Answer 1

• Based on their compositions, structures and on conjugate acid-base relationships ; the bases shown below in order of increasing :

(a) H3PO4 < H2PO4 - < HPO4 2- < PO4 3-

(b) ClO4 - < SO4 2- < AsO4 3- < AsO3 3-

(c) I- < Br- < NH2 - < NH 2-

Va of Propionic acid = 1.3 x 10-5 Stength (C) = 0.00860 M H&q-C00€ +H@ HC3COOH. (1-x)C we 1 xc - Ka= x²C > XC = ukic I ka Degree of ionisation 1.3x10-5 0.00860 = 0.03887 7 % of ionisation = 3.89% 33.89% - (weak base + salt of weak base) = buffer na of weak base=1.381055 According to Henderson equation, pH = -log ka + long lemo n 7 -log[ht] = -log(1.3 x 10-5) + log ovog mo note bare

= 5:03074 [1t+] = (10)-503074 = 9.32 x 10-6 c= 0. 00 86 (kc) - 9:32 x 106 9.32X.1016 2 0.00860 = 0001083 i': % jonisation = 0.108 %