Question

Part 2: pH and pOH Calculations 1) You dissolve 0.1500 moles of formic acid (monoprotic, K = 1.8 x 10-) in 2.50 L of water. Calculate the pH of this solution. Use the quadratic formula for this calculation (just to prove you can do it!), i.e., don't use the approximation that x «[...) 2) You dissolve 15.0 grams of propanoic acid (monoprotic, MW = 74.08 g/mol, Ka = 1.3 X 10"") in 95.00 ml of water. Calculate the pol of this solution.

Answer 1

0.15 mol formic acid (Hcool in 2.5 lts water molarity = moles = [H COOH] = Orbis = 0.06mm It cooh - Ht + H coot Ka=1-8x154 0-06m & o F. initial 6 ze ze . 0.06-2e oln a -= 0-06-2e ze=3-2x10 3 ka= [HT] CHCoo]. 1.8x104 [H COOH) 0 [H+) = x= 3-2 x103 m plt = -_JCH +) = -log (3-2X153) = PA – 2.57 answers Is Scanned with CamScanner IIIIII