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Question 2 (1 point) The standard reduction potential of the and 12/1 and Agt/Ag couples are +0.54 and +0.80 V, respectively

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Answer #1

Here, I2 is reduced to I-, so I2/I- is the cathode and Ag+/Ag is anode.

Ecell = Ecathode - Eanode

Ecell = 0.54 -0.80

Ecell = - 0.26 V, it is negative.

Therefore, false is the correct answer.

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