Question

CHEM 121 - Extra Credit (2020) 3. (5 pts) Morphine is an opioid medication and painkiller. A morphine derivative (MW-354.41 g/mol) has the following composition: 67.78% C, 6.26% H, 7.90% N, and 18.06% 0. Determine both the empirical and molecular formula for this compound. Show all work for complete credit.

Answer 1

Assume 100 gram of Morphine then. Amount of carbon = 6.7.78 5.6483 mole. Aument of Hydrogen = 6.26 = 6.26 mole 12 - ota Amount of with gen = 7.90- 0.564 mole 14 Amount of oxygen = 13.06 = 1.128 mole Moles of Nitrogen is smallest then calculate the ratio of uncias element ast Carbon = 5.6483, 10 Nitrogen = 1 Hydrogen = 6.2 b = " orggen = 1.123 = 2 So, empirical formula is [ChoMi, 002] Molal Mas from empirical formada = 16x12 +11+14+32 0.564 0.574 0.564 = 120 til +14+32 = 177 grau/mole for Molecdal formula a Molal Mass (given) Melal Mald (called 354. 177 = 2 0 Moleculae fromula is kiot, n,O2) . Co Haz Oq Oy) Any Please give good fatly.