Question

Calculate the solubility at 25 °C of AgCl in pure water and in a 0.0140 M AgNO3 solution. You'll find K, data in the ALEKS Data tab. Round both of your answers to 2 significant digits. solubility in pure water: نامه نامه solubility in 0.0140 M AgNO3 solution: 0 x 6 ?

Answer 1

Date Answer & Ksp= 1.76 × 10-10 for Agcl. C D Agce - Agt + co - Kap = [A +] [ce ] - 1.76x10-10 = ss. = 1.33 x 105 M. In g = sx molar mass of Agcl. = 1.33 x 105 x 143.32 g/l = 1.9 * 10-39 due to water) only - Answer - Agce Ag+ + ce Sto.0140 S. due to AgNO3- Ksp = (sto.0140).S [ As Ksp is very small.so, 1.76X100 = 0.0140.5 S+0.0140 ~ 0.01401 S = 1.26 x 10-8 M. In g = molowity x molarmass = 1.264109 x 143:37 1.8 x 10-6 a (for 0.0140 M AgNO3). ANSWER