Question

What is the solubility in moles/liter for magnesium carbonate at 25 oC given a Ksp value of 1.0 x 10-5. Write using scientific notation and use 1 or 2 decimal places (even though this is strictly incorrect!)

Answer 1

Solubility – Solubility is defined as maximum amount of solute theit.can be dissolved in a given amount of solvent at constant temperature. Mgcas ...Mg CO2 (s) + 40 = myopicaq) + coś cosa initially a (concentration) at equilibrium x-5 5 5 5 Kep = [nget][cost] Ksp = 5.5 ksp=s² M S = VKSP - S= Vixios Solubility 15 = 3.16247 X103 mol Lo?)

• P.s. - Since concentration of pure solid and liquid remains constant, so my CO₂ (s) and Hadle) does not appear in equilibrium expression. ie k = [Mgot] [coger] [ mglog (c)] [ M20 copy K [mg CO2 (s)] [Hall4)] = [ mg as I (co? ] commande Constant cənastout and defining new constant, ksp = k [ng cosas] (helo] » Ksp = Ling et] [cost]]

* concentration of pure solid and liquid remains constant. Proof- CaCO3 (3) ² Cao(s) + Cola (9) ik,= 1004 concentration = moves volume massa Molar mass x volume? A molese buiueniass) molarinas density t constant I density= marime] ogo volume ! Molar Mass + constant L a constant JUOOOO to for above reaction, K = r cao(s) ] [ CO2 (9)] [cacog (s)] is, k. [cacog (s) je cena constant - [ coelgo] * constant [coalgi K x constant constant defining new constant, Kc = kc = [cong (g)]] equilibrium constant will be independent of mass of a coz and cao.